5v^2-10x+1=22

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Solution for 5v^2-10x+1=22 equation:


Simplifying
5v2 + -10x + 1 = 22

Reorder the terms:
1 + 5v2 + -10x = 22

Solving
1 + 5v2 + -10x = 22

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 5v2 + -1 + -10x = 22 + -1

Reorder the terms:
1 + -1 + 5v2 + -10x = 22 + -1

Combine like terms: 1 + -1 = 0
0 + 5v2 + -10x = 22 + -1
5v2 + -10x = 22 + -1

Combine like terms: 22 + -1 = 21
5v2 + -10x = 21

Add '10x' to each side of the equation.
5v2 + -10x + 10x = 21 + 10x

Combine like terms: -10x + 10x = 0
5v2 + 0 = 21 + 10x
5v2 = 21 + 10x

Divide each side by '5'.
v2 = 4.2 + 2x

Simplifying
v2 = 4.2 + 2x

Reorder the terms:
-4.2 + v2 + -2x = 4.2 + 2x + -4.2 + -2x

Reorder the terms:
-4.2 + v2 + -2x = 4.2 + -4.2 + 2x + -2x

Combine like terms: 4.2 + -4.2 = 0.0
-4.2 + v2 + -2x = 0.0 + 2x + -2x
-4.2 + v2 + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
-4.2 + v2 + -2x = 0

The solution to this equation could not be determined.

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